14x^2-68x-10=0

Solution for 14x^2-68x-10=0 equation:

14x^2-68x-10=0

a = 14; b = -68; c = -10;
Δ = b2-4ac
Δ = -682-4·14·(-10)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-72}{2*14}=\frac{-4}{28}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+72}{2*14}=\frac{140}{28}
=5
$